Evan Martin (evan) wrote in evan_tech,
Evan Martin

another monad to become familiar with

A guy at work who's ten times the Haskell hacker I'll ever be pointed me at this thread, where someone is wondering whether a pattern of applying multiple functions to the same value can be generalized. As an example they provide:
eval :: (b->c->d) -> (a->b) -> (a->c) -> (a->d)
eval f g1 g2 a = f (g1 a) (g2 a)

which could be used to e.g. apply something to both halves of a pair in one go:
(eval (==) fst snd) somePair
This seems obscure enough to me, but the response they get, on a simpler implementation, is done in a single word.

The answer? eval = liftM2, because there's some instance for functions themselves: ((->) a) is an instance of MonadReader, which I don't yet fully get. I need to learn how functional dependencies work first, I think.
Tags: haskell

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